(4x+y)(2x^2-xy+5y^2)=

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Solution for (4x+y)(2x^2-xy+5y^2)= equation: 


Simplifying
(4x + y)(2x2 + -1xy + 5y2) = 0

Reorder the terms:
(4x + y)(-1xy + 2x2 + 5y2) = 0

Multiply (4x + y) * (-1xy + 2x2 + 5y2)
(4x * (-1xy + 2x2 + 5y2) + y(-1xy + 2x2 + 5y2)) = 0
((-1xy * 4x + 2x2 * 4x + 5y2 * 4x) + y(-1xy + 2x2 + 5y2)) = 0

Reorder the terms:
((20xy2 + -4x2y + 8x3) + y(-1xy + 2x2 + 5y2)) = 0
((20xy2 + -4x2y + 8x3) + y(-1xy + 2x2 + 5y2)) = 0
(20xy2 + -4x2y + 8x3 + (-1xy * y + 2x2 * y + 5y2 * y)) = 0
(20xy2 + -4x2y + 8x3 + (-1xy2 + 2x2y + 5y3)) = 0

Reorder the terms:
(20xy2 + -1xy2 + -4x2y + 2x2y + 8x3 + 5y3) = 0

Combine like terms: 20xy2 + -1xy2 = 19xy2
(19xy2 + -4x2y + 2x2y + 8x3 + 5y3) = 0

Combine like terms: -4x2y + 2x2y = -2x2y
(19xy2 + -2x2y + 8x3 + 5y3) = 0

Solving
19xy2 + -2x2y + 8x3 + 5y3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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